Respuesta:
Explicación paso a paso:
a) [tex]\sqrt[3]{\frac{1}{8} } = \sqrt[3]{(\frac{1}{2} )^{3} } = \frac{1}{2}[/tex]
b) [tex]\sqrt[]{\frac{9}{144} } = \sqrt[]{(\frac{3}{12} )^{2} } = \frac{3}{12}= \frac{1}{4}[/tex]
c) [tex]\sqrt[5]{-\frac{1}{32} } = \sqrt[5]{(-\frac{1}{2} )^{5} } =- \frac{1}{2}[/tex]
d) [tex]\sqrt{\frac{49}{16} } = \sqrt{(\frac{7}{4} )^{2} } = \frac{7}{4}[/tex]
e) [tex]\sqrt[4]{\frac{1}{16} } = \sqrt[4]{(\frac{1}{2} )^{4} } = \frac{1}{2}[/tex]
f) [tex]\sqrt[3]{-\frac{27}{125} } = \sqrt[3]{(-\frac{3}{5} )^{3} } = -\frac{3}{5}[/tex]
g) [tex]\sqrt{\frac{1}{625} } = \sqrt{(\frac{1}{25} )^{2} } = \frac{1}{25}[/tex]
h) [tex]\sqrt[4]{\frac{81}{256} } = \sqrt[4]{(\frac{3}{4} )^{4} } = \frac{3}{4}[/tex]
i) [tex]\sqrt[7]{-\frac{128}{10000000} } = \sqrt[7]{(-\frac{2}{10} )^{7} } = -\frac{2}{10}[/tex]
j) [tex]\sqrt[6]{\frac{1}{64} } = \sqrt[6]{(\frac{1}{2} )^{6} } = \frac{1}{2}[/tex]
