ROSALIA110154GO ROSALIA110154GO Matemáticas contestada (3x) + (4x) = (–3x) + (4x) =(3m) + (4m2) + (4n) =(2b2 + 4c + 3a3) + (5a + 3b + c2) = (3x) + (–4x) =(–3x) + (–4x) = (2x) + (2x2) = (–2x) + (2x2) = (2x) + (–2x2) = (–2x) + (–2x2) = (–3m) + (4m2) + (4n) = (–3m) + (–4m2) + (4n) =(–3m) + (4m2) + (–4n) = (–2b2 + 4c + 3a3) + (5a + 3b – c2) = (2b2 + 4c – 3a3) + (5a + 3b – c2) = (2b2 – 4c + 3a3) + (5a + 3b + c2) = (2b2 + 4c + 3a3) + (–5a + 3b + c2) = ayudaa