Respuesta :
[tex]a) {x}^{3} - \frac{1}{2} x = \\ {4}^{3} - \frac{1}{2} \times 4 = \\ 64 - 2 = \\ 62 [/tex]
[tex]b) {x}^{3} - \frac{1}{2} x = \\ {( - 2)}^{3} - \frac{1}{2} \times ( - 2) = \\ - 8 - ( - 1) = \\ - 8 + 1 = \\ - 7[/tex]
[tex]a) {x}^{3} - \frac{1}{2} x = \\ {4}^{3} - \frac{1}{2} \times 4 = \\ 64 - 2 = \\ 62 [/tex]
[tex]b) {x}^{3} - \frac{1}{2} x = \\ {( - 2)}^{3} - \frac{1}{2} \times ( - 2) = \\ - 8 - ( - 1) = \\ - 8 + 1 = \\ - 7[/tex]